Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int size = nums.size();
int sum = 0, maxSum = nums[0];
for (int i = 0; i < size; i++) {
if (sum < 0) {
sum = nums[i];
} else {
sum += nums[i];
}
maxSum = max(maxSum, sum);
}
return maxSum;
}
};
For example, given the array
the contiguous subarray
[-2,1,-3,4,-1,2,1,-5,4]
,the contiguous subarray
[4,-1,2,1]
has the largest sum = 6
.public:
int maxSubArray(vector<int>& nums) {
int size = nums.size();
int sum = 0, maxSum = nums[0];
for (int i = 0; i < size; i++) {
if (sum < 0) {
sum = nums[i];
} else {
sum += nums[i];
}
maxSum = max(maxSum, sum);
}
return maxSum;
}
};