Problem:
Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
Solution:
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode *p, TreeNode *q) {
if (p == NULL && q == NULL)
return true;
else if (p != NULL && q != NULL)
return p -> val == q -> val &&
isSameTree(p -> left, q -> left) &&
isSameTree(p -> right, q -> right);
else
return false;
}
};
Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
Solution:
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode *p, TreeNode *q) {
if (p == NULL && q == NULL)
return true;
else if (p != NULL && q != NULL)
return p -> val == q -> val &&
isSameTree(p -> left, q -> left) &&
isSameTree(p -> right, q -> right);
else
return false;
}
};
No comments:
Post a Comment