Given an unsorted integer array, find the first missing positive integer.
For example,
Given
[1,2,0]
return 3
,and
[3,4,-1,1]
return 2
.
Your algorithm should run in O(n) time and uses constant space.
Solution:
class Solution {
public:
int firstMissingPositive(int A[], int n) {
for (int cur = 0; cur < n; cur++) {
if (A[cur] <= 0) {
A[cur] = n + 1;
}
}
for (int i = 0; i < n; i++)
if (abs(A[i]) <= n && A[abs(A[i]) - 1] > 0)
A[abs(A[i]) - 1] *= -1;
for (int i = 0; i < n; i++)
if (A[i] > 0) {
return i + 1;
}
return n + 1;
}
};
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