Problem:
Solution:
class Solution {
public:
int majorityElement(vector<int> &num) {
int elem, count = 0;
int size = num.size();
if (size == 1)
return num[0];
for (int i = 0; i < size; i++) {
if (count == 0) {
elem = num[i];
count = 1;
} else if (elem == num[i]) {
count++;
} else {
count--;
}
}
return elem;
}
};
Given an array of size n, find the majority element. The majority element is the element that appears more than
⌊ n/2 ⌋
times.
You may assume that the array is non-empty and the majority element always exist in the array.
Solution:
class Solution {
public:
int majorityElement(vector<int> &num) {
int elem, count = 0;
int size = num.size();
if (size == 1)
return num[0];
for (int i = 0; i < size; i++) {
if (count == 0) {
elem = num[i];
count = 1;
} else if (elem == num[i]) {
count++;
} else {
count--;
}
}
return elem;
}
};
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