Problem:
Solution:
class Solution {
public:
bool isValid(string s) {
stack<char> tmp;
int size = s.size();
for (int i = 0; i < size; i++) {
if (s[i] == '(' || s[i] == '{' || s[i] == '[')
tmp.push(s[i]);
else if (s[i] == ')') {
if (tmp.empty() || tmp.top() != '(')
return false;
tmp.pop();
} else if (s[i] == '}') {
if (tmp.empty() || tmp.top() != '{')
return false;
tmp.pop();
} else if (s[i] == ']') {
if (tmp.empty() || tmp.top() != '[')
return false;
tmp.pop();
}
}
// Assuming empty string returns true;
if (tmp.empty())
return true;
return false;
}
};
Given a string containing just the characters
'(', ')', '{', '}', '[' and ']', determine if the input string is valid.
The brackets must close in the correct order,
"()" and "()[]{}" are all valid but "(]" and "([)]" are not.Solution:
class Solution {
public:
bool isValid(string s) {
stack<char> tmp;
int size = s.size();
for (int i = 0; i < size; i++) {
if (s[i] == '(' || s[i] == '{' || s[i] == '[')
tmp.push(s[i]);
else if (s[i] == ')') {
if (tmp.empty() || tmp.top() != '(')
return false;
tmp.pop();
} else if (s[i] == '}') {
if (tmp.empty() || tmp.top() != '{')
return false;
tmp.pop();
} else if (s[i] == ']') {
if (tmp.empty() || tmp.top() != '[')
return false;
tmp.pop();
}
}
// Assuming empty string returns true;
if (tmp.empty())
return true;
return false;
}
};
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