Sunday, January 26, 2020

Search a 2D Matrix II

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
  • Integers in each row are sorted in ascending from left to right.
  • Integers in each column are sorted in ascending from top to bottom.
Example:
Consider the following matrix:
[
  [1,   4,  7, 11, 15],
  [2,   5,  8, 12, 19],
  [3,   6,  9, 16, 22],
  [10, 13, 14, 17, 24],
  [18, 21, 23, 26, 30]
]
Given target = 5, return true.
Given target = 20, return false.

class Solution {
public:
    bool searchMatrix(vector<vector<int>>& matrix, int target) {
        int rows = matrix.size();
        if (rows == 0) {
            return false;
        }
        int cols = matrix[0].size();
        int rows_st = 0;
        int cols_end = cols;
        while (rows_st < rows && cols_end > 0) {
            int row = rows_st, col = cols_end - 1;
            if (matrix[row][col] == target) {
                return true;
            } else if (matrix[row][col] > target) {
                cols_end--;
            } else {
                rows_st++;
            }
        }
        return false;
    }
};

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