Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted in ascending from left to right.
- Integers in each column are sorted in ascending from top to bottom.
Example:
Consider the following matrix:
[ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23, 26, 30] ]
Given target =
5
, return true
.
Given target =
20
, return false
.
class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target) {
int rows = matrix.size();
if (rows == 0) {
return false;
}
int cols = matrix[0].size();
int rows_st = 0;
int cols_end = cols;
while (rows_st < rows && cols_end > 0) {
int row = rows_st, col = cols_end - 1;
if (matrix[row][col] == target) {
return true;
} else if (matrix[row][col] > target) {
cols_end--;
} else {
rows_st++;
}
}
return false;
}
};
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