Alice has a
hand
of cards, given as an array of integers.
Now she wants to rearrange the cards into groups so that each group is size
W
, and consists of W
consecutive cards.
Return
true
if and only if she can.
Example 1:
Input: hand = [1,2,3,6,2,3,4,7,8], W = 3 Output: true Explanation: Alice'shand
can be rearranged as[1,2,3],[2,3,4],[6,7,8]
.
Example 2:
Input: hand = [1,2,3,4,5], W = 4 Output: false Explanation: Alice'shand
can't be rearranged into groups of4
.
Note:
1 <= hand.length <= 10000
0 <= hand[i] <= 10^9
1 <= W <= hand.length
class Solution {
public:
bool isNStraightHand(vector<int>& hand, int W) {
int n = hand.size();
if(n%W!=0){
return false;
}
map<int,int> mp;
for(int i = 0; i < n ; i++){
mp[hand[i]]++;
}
while(!mp.empty()){
int v = mp.begin()->first;
for(int i = 0; i < W; i++){
if(!mp[v+i]){
return false;
}else{
mp[v+i]--;
if(!mp[v+i]){
mp.erase(v+i);
}
}
}
}
return true;
}
};
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