We are given a binary tree (with root node root
), a target
node, and an integer value K
.
Return a list of the values of all nodes that have a distance K
from the target
node. The answer can be returned in any order.
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], target = 5, K = 2
Output: [7,4,1]
Explanation:
The nodes that are a distance 2 from the target node (with value 5)
have values 7, 4, and 1.
Note that the inputs "root" and "target" are actually TreeNodes.
The descriptions of the inputs above are just serializations of these objects.
Note:
- The given tree is non-empty.
- Each node in the tree has unique values
0 <= node.val <= 500
.
- The
target
node is a node in the tree.
0 <= K <= 1000
.
root
), a target
node, and an integer value K
.K
from the target
node. The answer can be returned in any order.
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], target = 5, K = 2 Output: [7,4,1] Explanation: The nodes that are a distance 2 from the target node (with value 5) have values 7, 4, and 1. Note that the inputs "root" and "target" are actually TreeNodes. The descriptions of the inputs above are just serializations of these objects.
Note:
- The given tree is non-empty.
- Each node in the tree has unique values
0 <= node.val <= 500
. - The
target
node is a node in the tree. 0 <= K <= 1000
.
Approach 1: Annotate Parent
Intuition
If we know the parent of every node
x
, we know all nodes that are distance 1
from x
. We can then perform a breadth first search from the target
node to find the answer.
Algorithm
We first do a depth first search where we annotate every node with information about it's parent.
After, we do a breadth first search to find all nodes a distance
K
from the target
.
Complexity Analysis
- Time Complexity: , where is the number of nodes in the given tree.
- Space Complexity: .
Approach 2: Percolate Distance
Intuition
From
root
, say the target
node is at depth 3
in the left branch. It means that any nodes that are distance K - 3
in the right branch should be added to the answer.
Algorithm
Traverse every
node
with a depth first search dfs
. We'll add all nodes x
to the answer such that node
is the node on the path from x
to target
that is closest to the root
.
To help us,
dfs(node)
will return the distance from node
to the target
. Then, there are 4 cases:- If
node == target
, then we should add nodes that are distanceK
in the subtree rooted attarget
. - If
target
is in the left branch ofnode
, say at distanceL+1
, then we should look for nodes that are distanceK - L - 1
in the right branch. - If
target
is in the right branch ofnode
, the algorithm proceeds similarly. - If
target
isn't in either branch ofnode
, then we stop.
In the above algorithm, we make use of the auxillary function
subtree_add(node, dist)
which adds the nodes in the subtree rooted at node
that are distance K - dist
from the given node
.
Complexity Analysis
- Time Complexity: , where is the number of nodes in the given tree.
- Space Complexity: .
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