Given a binary array nums
, return the maximum length of a contiguous subarray with an equal number of 0
and 1
.
Example 1:
Input: nums = [0,1] Output: 2 Explanation: [0, 1] is the longest contiguous subarray with an equal number of 0 and 1.
Example 2:
Input: nums = [0,1,0] Output: 2 Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1.
Constraints:
1 <= nums.length <= 105
nums[i]
is either0
or1
.
class Solution {
public:
int findMaxLength(vector<int>& nums) {
unordered_map<int, int> mp;
mp[0] = -1;
int ans = 0;
int counter = 0;
for (int i = 0; i < nums.size(); i++) {
if (nums[i] == 1) {
counter++;
} else {
counter--;
}
if (mp.count(counter) != 0) {
ans = max(ans, i - mp[counter]);
} else {
mp[counter] = i;
}
}
return ans;
}
};
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